I'm not sure what you are trying to do with enumerate, but if a is a dictionary, you probably want to use the keys, like this: > a = th day of Christmas". import pandas as pd print pd.daterange (start'', end'', freq'M') You can change the frequency of generating dates by setting freq as D, M, Q, Y (daily, monthly, quarterly, yearly ) Share. for i in range(10): for k in range(10): resi,j dosomething(i+1, 5k+5) don't forget range(M) starts at 0 and ends at M. result numpy.zeros((n,m), dtypefloat) I'm assuming your results are float. The range function generates a sequence of numbers, starting from 0 by default, and increments by 1 (also by default), and stops before a specified number. Update following additional comments on your question and the accepted answer You can generate a series of date between two dates using the pandas library simply and trustfully. var num range(1,6) for x in num: if num 3: print fizz elif num 5: print buzz else: print num output: Traceback (most recent call last): File. I suggest you do your loops to match the indices of the result in the result array rather than the parameters in your computational function. You can use the range function in a for loop in Python to repeat a block of code a specific number of times. ![]() Trying to fit everything on one line is rarely "Pythonic". The start argument is the starting number. Or those elements that are xyz but not in a: > sorted(set(xyz).difference(a))īut for a more complicated loop you may want to flatten it by iterating over a well-named generator expression and/or calling out to a well-named function. The range() function in Python is often used in for statements to define the number of loop iterations. The Pythonic way of getting the sorted intersection of two sets is: > sorted(set(a).intersection(xyz)) ![]() As per The Zen of Python (if you are wondering whether your code is "Pythonic", that's the place to go):
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